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[LeetCode] 2340. Minimum Adjacent Swaps to Make a Valid Array 본문
Computer Science/Algorithms & Data Structures
[LeetCode] 2340. Minimum Adjacent Swaps to Make a Valid Array
focalpoint 2024. 7. 2. 16:19https://leetcode.com/problems/minimum-adjacent-swaps-to-make-a-valid-array/description/
1. Python
class Solution:
def minimumSwaps(self, nums: List[int]) -> int:
if len(nums) <= 1:
return 0
minVal = min(nums)
maxVal = max(nums)
for i in range(len(nums)):
if nums[i] == minVal:
minIdx = i
break
for i in range(len(nums)-1, -1, -1):
if nums[i] == maxVal:
maxIdx = i
break
if minIdx == maxIdx:
return 0
elif minIdx < maxIdx:
return minIdx + len(nums) - maxIdx - 1
else:
return minIdx + len(nums) - maxIdx - 2
2. C++
class Solution {
public:
int minimumSwaps(vector<int>& nums) {
if (nums.size() <= 1) return 0;
int minVal = *min_element(nums.begin(), nums.end());
int maxVal = *max_element(nums.begin(), nums.end());
int minIdx, maxIdx;
for (int i=0; i<nums.size(); i++) {
if (nums[i] == minVal) {
minIdx = i;
break;
}
}
for (int i=nums.size()-1; i>=0; i--) {
if (nums[i] == maxVal) {
maxIdx = i;
break;
}
}
if (minIdx == maxIdx) return 0;
else if (minIdx < maxIdx) return minIdx + nums.size() - maxIdx - 1;
else return minIdx + nums.size() - maxIdx - 2;
}
};
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