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LeetCode: 31. Next Permutation 본문
class Solution:
def nextPermutation(self, nums: List[int]) -> None:
i = len(nums) - 1
while i - 1 >= 0 and nums[i-1] >= nums[i]:
i -= 1
if i == 0:
return nums.sort()
swap_idx, swap_val = None, int(1e9)
for j in range(i, len(nums)):
if nums[j] > nums[i-1] and nums[j] < swap_val:
swap_val = nums[j]
swap_idx = j
nums[i-1], nums[swap_idx] = nums[swap_idx], nums[i-1]
nums[i:] = sorted(nums[i:])
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