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- 315. Count of Smaller Numbers After Self
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LeetCode: 43. Multiply Strings 본문
class Solution:
def multiply(self, num1: str, num2: str) -> str:
if num1 == '0' or num2 == '0':
return '0'
ret = [0] * (len(num1) + len(num2))
for i in range(len(num1)-1, -1, -1):
carry = 0
for j in range(len(num2)-1, -1, -1):
temp = ret[i+j+1] + int(num1[i]) * int(num2[j]) + carry
carry = temp // 10
ret[i+j+1] = temp % 10
ret[i] = carry
ret = ''.join(map(str, ret))
return ret.lstrip('0')
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