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목록25. Reverse Nodes in k-Group (1)
Scribbling
LeetCode: 25. Reverse Nodes in k-Group
Recursion solution. Time Complexity: O(N), Memory Complexity: O(1) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def reverseKGroup(self, head: Optional[ListNode], k: int) -> Optional[ListNode]: return self.helper(head, k) def helper(self, node, k): if not node: return None cur = node for i in ran..
Computer Science/Coding Test
2021. 8. 25. 22:55