목록6. ZigZag Conversion (1)

Scribbling

LeetCode: 6. ZigZag Conversion

class Solution: def convert(self, s: str, numRows: int) -> str: if numRows == 1: return s board = [[] for _ in range(numRows)] denom = 2 * numRows - 2 for i, char in enumerate(s): remainder = i % denom if remainder < numRows: board[remainder].append(char) else: board[2 * numRows - remainder - 2].append(char) ret = '' for i in range(len(board)): for j in board[i]: ret += j return ret
Computer Science/Coding Test 2021. 8. 16. 15:55
이전 Prev 1 Next 다음