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목록Swap Nodes in Pairs (1)
Scribbling
LeetCode: 24. Swap Nodes in Pairs
문제의 쉬운 version... 재귀를 이용해서 푸는 방법을 익혀두자. # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def swapPairs(self, head: Optional[ListNode]) -> Optional[ListNode]: k = 2 count, node = 0, head while node and count < k: node = node.next count += 1 if count < k: return head n..
Computer Science/Coding Test
2021. 8. 26. 20:18