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목록candy (1)
Scribbling
LeetCode: 135. Candy
Key idea: one's number of candies is affected by all the left and right neighbors. So we iterate the list twice, forward and backward. class Solution: def candy(self, ratings: List[int]) -> int: n = len(ratings) candies = [1] * n # forward pass for i in range(1, n): if ratings[i] > ratings[i-1]: candies[i] = candies[i-1] + 1 # backward pass for i in range(n-2, -1, -1): if ratings[i] > ratings[i+..
Computer Science/Coding Test
2022. 2. 3. 10:35