목록31. Next Permutation (1)

Scribbling

LeetCode: 31. Next Permutation

class Solution: def nextPermutation(self, nums: List[int]) -> None: i = len(nums) - 1 while i - 1 >= 0 and nums[i-1] >= nums[i]: i -= 1 if i == 0: return nums.sort() swap_idx, swap_val = None, int(1e9) for j in range(i, len(nums)): if nums[j] > nums[i-1] and nums[j] < swap_val: swap_val = nums[j] swap_idx = j nums[i-1], nums[swap_idx] = nums[swap_idx], nums[i-1] nums[i:] = sorted(nums[i:])
Computer Science/Coding Test 2021. 9. 9. 22:40
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